In Young's double slit experiment, light of wavelength lambda passes through the double-slit and forms interference fringes on a screen 1.2 m away. If the difference between 3rd order maximum and 3 rd order minimum is 0.18 cm and the slits are 0.02 cm apart, then λ is

Question

In Young's double slit experiment, light of wavelength lambda passes through the double-slit and forms interference fringes on a screen 1.2 m away. If the difference between 3rd order maximum and 3 rd order minimum is 0.18 cm and the slits are 0.02 cm apart, then λ is (A) 1200 nm (B) 450 nm (C) 600 nm (D) 300 nm

Tardigrade Admin · Accepted Answer

Distance between 3rd order minima and 3rd order maxima is (β/2) (β/2)=0.18 cm β=0.36 cm β=(D λ/d) ∴ λ=600 nm

Q. In Young's double slit experiment, light of wavelength lambda passes through the double-slit and forms interference fringes on a screen $1.2 m$ away. If the difference between $3^{r d}$ order maximum and $3^{r d}$ order minimum is $0.18 c m$ and the slits are $0.02 c m$ apart, then $λ$ is

1200 nm

450 nm

600 nm

300 nm

Distance between
$3^{r d}$ order minima and $3^{r d}$ order maxima is $\frac{β}{2}$
$\frac{β}{2} = 0.18 c m$
$β = 0.36 c m$
$β = \frac{D λ}{d}$
$∴ λ = 600 nm$

Q. In Young's double slit experiment, light of wavelength lambda passes through the double-slit and forms interference fringes on a screen 1.2m away. If the difference between 3rd order maximum and 3rd order minimum is 0.18cm and the slits are 0.02cm apart, then λ is