In Young's double-slit experiment interference bands are produced on the screen placed at 1.5 m from two slits 0.15 mm apart and illuminated by the light of wavelength 6000 Å . If the screen is now taken away from the slits by 50 cm then find the change in fringe width (in mm)?

Question

In Young's double-slit experiment interference bands are produced on the screen placed at 1.5 m from two slits 0.15 mm apart and illuminated by the light of wavelength 6000 Å . If the screen is now taken away from the slits by 50 cm then find the change in fringe width (in mm)? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

D2-D1=50 cm ; D1=1.5 m=150 cm λ =6000 â«=6000× 10- 8 cm ; d=0.15 mm Change in fringe width Δ β=( mathrmD2- mathrmD1) (λ/ mathrmd)=(50 × 6000 × 10-8/0.15 × 10-1) Δ β =(20 × 10- 4/10- 3)=2× 10- 1 cm=2mm Δ β =2 mm

Q. In Young's double-slit experiment interference bands are produced on the screen placed at 1.5 m from two slits 0.15 mm apart and illuminated by the light of wavelength 6000Å . If the screen is now taken away from the slits by 50 cm then find the change in fringe width (in mm)?

D2​−D1​=50cm ; D1​=1.5m=150cm λ=6000Å=6000×10−8cm ; d=0.15mm Change in fringe width Δβ=(D2​−D1​)dλ​=0.15×10−150×6000×10−8​ Δβ=10−320×10−4​=2×10−1cm=2mm Δβ=2mm

Q. In Young's double-slit experiment interference bands are produced on the screen placed at 1.5 m from two slits 0.15 mm apart and illuminated by the light of wavelength $6000 Å$ . If the screen is now taken away from the slits by 50 cm then find the change in fringe width (in mm)?