In Young's double slit experiment, if d, D and λ represent, the distance between the slits, the distance of the screen from the slits and wavelength of light used respectively, then the band width is inversely proportional to

Question

In Young's double slit experiment, if d, D and λ represent, the distance between the slits, the distance of the screen from the slits and wavelength of light used respectively, then the band width is inversely proportional to (A) λ (B) d (C) D (D) λ2

Tardigrade Admin · Accepted Answer

The band width is inversely proportional to the distance between the slits d as β = (λ D/d) , β propto (1/d)

Q. In Young's double slit experiment, if $d$ , $D$ and $λ$ represent, the distance between the slits, the distance of the screen from the slits and wavelength of light used respectively, then the band width is inversely proportional to

$λ$

$d$

$D$

$λ^{2}$

$D^{2}$

The band width is inversely proportional to the distance between the slits $d$ as $β = \frac{λ D}{d}, β \propto \frac{1}{d}$

Q. In Young's double slit experiment, if d, D and λ represent, the distance between the slits, the distance of the screen from the slits and wavelength of light used respectively, then the band width is inversely proportional to

λ

d

D

λ2

D2

The band width is inversely proportional to the distance between the slits d as β=dλD​,β∝d1​

Q. In Young's double slit experiment, if $d$ , $D$ and $λ$ represent, the distance between the slits, the distance of the screen from the slits and wavelength of light used respectively, then the band width is inversely proportional to

$λ$

$d$

$D$

$λ^{2}$

$D^{2}$

The band width is inversely proportional to the distance between the slits $d$ as $β = \frac{λ D}{d}, β \propto \frac{1}{d}$