In Young's double slit arrangement, slits are separated by a gap of 0.5 mm, and the screen is placed at a distance of 0.5 m from them. The distance between the first and the third bright fringe formed when the slits are illuminated by a monochromatic light of 5890 mathringA is :-

Question

In Young's double slit arrangement, slits are separated by a gap of 0.5 mm, and the screen is placed at a distance of 0.5 m from them. The distance between the first and the third bright fringe formed when the slits are illuminated by a monochromatic light of 5890 mathringA is :- (A) 1178 × 10-9 m (B) 1178 × 10-6 m (C) 1178 × 10-12 m (D) 5890 × 10-7 m

Tardigrade Admin · Accepted Answer

β=(λ D/d)=(5890 × 10-10 × 0.5/0.5 × 10-3) =589 × 10-6 m Distance between first and third bright fringe is 2 β=2 × 589 × 10-6 m =1178 × 10-6 m

Q. In Young's double slit arrangement, slits are separated by a gap of 0.5 mm, and the screen is placed at a distance of 0.5 m from them. The distance between the first and the third bright fringe formed when the slits are illuminated by a monochromatic light of $5890$ $\overset{˚}{A}$ is :-

$1178 \times 1 0^{- 9} m$

$1178 \times 1 0^{- 6} m$

$1178 \times 1 0^{- 12} m$

$5890 \times 1 0^{- 7} m$

$β = \frac{λ D}{d} = \frac{5890 \times 1 0 ^{- 10} \times 0.5}{0.5 \times 1 0 ^{- 3}}$
$= 589 \times 1 0^{- 6} m$
Distance between first and third bright fringe is $2 β = 2 \times 589 \times 1 0^{- 6} m$
$= 1178 \times 1 0^{- 6} m$

Q. In Young's double slit arrangement, slits are separated by a gap of 0.5 mm, and the screen is placed at a distance of 0.5 m from them. The distance between the first and the third bright fringe formed when the slits are illuminated by a monochromatic light of 5890 A˚ is :-

1178×10−9m

1178×10−6m

1178×10−12m

5890×10−7m