In YDSE, if sources are incoherent, the intensity on screen is 13 I0. When these sources are coherent then minimum intensity on screen is I0. If maximum intensity produced by these coherent sources on screen is n2 I0, then find n.

Question

In YDSE, if sources are incoherent, the intensity on screen is 13 I0. When these sources are coherent then minimum intensity on screen is I0. If maximum intensity produced by these coherent sources on screen is n2 I0, then find n. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

dotI1+I2=13 I0 (√I1-√I2)2=I0 I1+I2-2 √I1 √I2=I0 2 √I1 √I2=12 I0 I max =13 I0+12 I0=25 I0=(5)2 I0

Q. In YDSE, if sources are incoherent, the intensity on screen is $13 I_{0}$ . When these sources are coherent then minimum intensity on screen is $I_{0}$ . If maximum intensity produced by these coherent sources on screen is $n^{2} I_{0}$ , then find $n$ .

$\dot{I}_{1} + I_{2} = 13 I_{0}$
$(I_{1} - I_{2})^{2} = I_{0}$
$I_{1} + I_{2} - 2 I_{1} I_{2} = I_{0}$
$2 I_{1} I_{2} = 12 I_{0}$
$I_{m a x} = 13 I_{0} + 12 I_{0} = 25 I_{0} = (5)^{2} I_{0}$

Q. In YDSE, if sources are incoherent, the intensity on screen is 13I0​. When these sources are coherent then minimum intensity on screen is I0​. If maximum intensity produced by these coherent sources on screen is n2I0​, then find n.

I˙1​+I2​=13I0​ (I1​​−I2​​)2=I0​ I1​+I2​−2I1​​I2​​=I0​ 2I1​​I2​​=12I0​ Imax​=13I0​+12I0​=25I0​=(5)2I0​

Q. In YDSE, if sources are incoherent, the intensity on screen is $13 I_{0}$ . When these sources are coherent then minimum intensity on screen is $I_{0}$ . If maximum intensity produced by these coherent sources on screen is $n^{2} I_{0}$ , then find $n$ .

$\dot{I}_{1} + I_{2} = 13 I_{0}$
$(I_{1} - I_{2})^{2} = I_{0}$
$I_{1} + I_{2} - 2 I_{1} I_{2} = I_{0}$
$2 I_{1} I_{2} = 12 I_{0}$
$I_{m a x} = 13 I_{0} + 12 I_{0} = 25 I_{0} = (5)^{2} I_{0}$