Question

In $XeO{F}_2$ molecule, the hybridisation of $Xe$ orbitals is

• A. $s{p}^3{d}^3$
• B. $s{p}^3{d}^2$
• C. $s{p}^{3}d$
• D. $s{p}^3$

Answer 1

Answer: (C)

In $XeO{F}_2$ molecule $Xe$ is $s{p}^{3}d$ hybridised. It has $3bp$ and $2lp$.