In Williamson's synthesis, ethoxyethane is prepared by:

Question

In Williamson's synthesis, ethoxyethane is prepared by: (A) passing ethanol over heated alumina (B) heating sodium ethoxide with ethyl bromide (C) treating ethyl alcohol with excess of H2SO4 at 430-440 K (D) heating ethanol with dry Ag2O

Tardigrade Admin · Accepted Answer

All the reactions given as choices , and are different methods of preparation of ethoxyethane but only the following is called Williamson synthesis. Williamson synthesis

so d . e t h o x i d e C_{2} H_{5} ON a + Et h y l b ro mi d e C_{2} H_{5} B r

Et h o x y e t han e C_{2} H_{5} - O - C_{2} H_{5} + N a B r

C_{2} H_{5} O H A l_{2} O_{3} C_{2} H_{5} O C_{2} H_{5}

C_{2} H_{5} O H H_{2} S o_{4} Δ430 - 440 C_{2} H_{5} O C_{2} H_{5}

C_{2} H_{5} O H A g_{2} O C_{2} H_{5} O C_{2} H_{5}

Above , and are the methods of preparing ethoxy ethane but not the Williamson's synthesis method.

Q. In Williamson's synthesis, ethoxyethane is prepared by:

passing ethanol over heated alumina

heating sodium ethoxide with ethyl bromide

treating ethyl alcohol with excess of $H_{2} S O_{4}$ at 430-440 K

heating ethanol with dry $A g_{2} O$

Q. In Williamson's synthesis, ethoxyethane is prepared by:

passing ethanol over heated alumina

heating sodium ethoxide with ethyl bromide

treating ethyl alcohol with excess of H2​SO4​ at 430-440 K

heating ethanol with dry Ag2​O

treating ethyl alcohol with excess of $H_{2} S O_{4}$ at 430-440 K

heating ethanol with dry $A g_{2} O$