In which of the following reactions, the underlined substance has been oxidized?

Question

In which of the following reactions, the underlined substance has been oxidized? (A)  underlineBr2 + underlineH2S arrow 2 HBr + S (B)  underline2HgCl2 + SnCl2 arrow underlineHg2Cl2 + SnCl4 (C) Cl2 + 2 underlineKI arrow 2KCl + underlineI2 (D)  underline2Cu2+ + 4 I-arrow underlineCu2I2 + I2

Tardigrade Admin · Accepted Answer

(a) overset text 0Br2 arrow overset text-1HBr (b) overset text +2HgCl2 arrow overset text +1 Hg2 Cl2 (c) 2 overset text-1KI arrow overset text0I2 (d) 2 Cu2+ arrow overset text+1Cu2 I2 Only in (c) the O.N. of I increases from - 1 to 0 and hence KI gets oxidised to I2.

Q. In which of the following reactions, the underlined substance has been oxidized?

$\underline{B r_{2}} + \underline{H_{2} S} \to 2 H B r + S$

$\underline{2 H g C l_{2}} + S n C l_{2} \to \underline{H g_{2} C l_{2}} + S n C l_{4}$

$C l_{2} + 2 \underline{K I} \to 2 K Cl + \underline{I_{2}}$

$\underline{2 C u^{2 +}} + 4 I^{-} \to \underline{C u_{2} I_{2}} + I_{2}$

(a) $B r_{2} 0 \to H B r -1$
(b) $H g C l_{2} +2 \to H g_{2} +1 C l_{2}$
(c) $2 K I -1 \to I_{2} 0$
(d) $2 C u^{2 +} \to C u_{2} +1 I_{2}$
Only in (c) the O.N. of I increases from - 1 to 0 and hence KI gets oxidised to $I_{2}$ .

Q. In which of the following reactions, the underlined substance has been oxidized?

Br2​​+H2​S​→2HBr+S

2HgCl2​​+SnCl2​→Hg2​Cl2​​+SnCl4​

Cl2​+2KI​→2KCl+I2​​

2Cu2+​+4I−→Cu2​I2​​+I2​

(a) Br2​ 0​→HBr-1 (b) HgCl2​ +2​→Hg2​ +1 ​Cl2​ (c) 2KI-1→I2​0​ (d) 2Cu2+→Cu2​+1​I2​ Only in (c) the O.N. of I increases from - 1 to 0 and hence KI gets oxidised to I2​.

$\underline{B r_{2}} + \underline{H_{2} S} \to 2 H B r + S$

$\underline{2 H g C l_{2}} + S n C l_{2} \to \underline{H g_{2} C l_{2}} + S n C l_{4}$

$C l_{2} + 2 \underline{K I} \to 2 K Cl + \underline{I_{2}}$

$\underline{2 C u^{2 +}} + 4 I^{-} \to \underline{C u_{2} I_{2}} + I_{2}$

(a) $B r_{2} 0 \to H B r -1$
(b) $H g C l_{2} +2 \to H g_{2} +1 C l_{2}$
(c) $2 K I -1 \to I_{2} 0$
(d) $2 C u^{2 +} \to C u_{2} +1 I_{2}$
Only in (c) the O.N. of I increases from - 1 to 0 and hence KI gets oxidised to $I_{2}$ .