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Tardigrade
Question
Chemistry
In which of the following pairs, the two species have identical bond order?
Q. In which of the following pairs, the two species have identical bond order?
1989
185
Chemical Bonding and Molecular Structure
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A
N
2
−
,
O
2
2
−
0%
B
N
2
−
,
O
2
−
5%
C
N
2
−
,
O
2
+
90%
D
O
2
+
,
N
2
2
−
5%
Solution:
Total number of electrons in
N
2
−
=
7
+
7
+
1
=
15
Total number of electrons in
N
2
2
−
7
+
7
+
2
=
16
Total number of electrons in
O
2
2
−
=
8
+
8
+
2
=
18
Total number of electrons in
O
2
−
=
8
+
8
+
1
=
17
Total number of electrons in
O
2
+
=
8
+
8
−
1
=
15
Configuration will be same as
N
2
−
and
O
2
+
contain the
same total number of electrons. Thus
N
2
−
and
O
2
+
has the same bond order.