In which of the following options the order of arrangement does not agree with the variation of property indicate against it ?

Question

In which of the following options the order of arrangement does not agree with the variation of property indicate against it ? (A) B < C < N < O (increasing first ionisation enthalpy) (B) I < Br < Cl < F (increasing electron gain enthalpy) (C) Li < Na < K < Rb (increasing metallic radius) (D) Al3+ + < Mg2 + < Na+ + < F- (increasing ionic size)

Tardigrade Admin · Accepted Answer

Ionisation enthalpy of N is greater than O because N has half filled p subshell. B < C < O < N (

I^{s t}

ionization enthalpy)

2 p^{1} 2 p^{2} 2 p^{4} 2 p^{3}

Electron gain enthalpy of F is less than Cl because in F small size of 2p orbital result in high electron density so inter electronic repulsion is high.
I < Br < F < Cl (electron gain enthalpy)

Q. In which of the following options the order of arrangement does not agree with the variation of property indicate against it ?

$B < C < N < O$ (increasing first ionisation enthalpy)

$I < B r < Cl < F$ (increasing electron gain enthalpy)

$L i < N a < K < R b$ (increasing metallic radius)

$A l^{3 +} + < M g^{2 +} < N a^{+} + < F -$ (increasing ionic size)

Q. In which of the following options the order of arrangement does not agree with the variation of property indicate against it ?

B<C<N<O (increasing first ionisation enthalpy)

I<Br<Cl<F (increasing electron gain enthalpy)

Li<Na<K<Rb (increasing metallic radius)

Al3++<Mg2+<Na++<F− (increasing ionic size)

$B < C < N < O$ (increasing first ionisation enthalpy)

$I < B r < Cl < F$ (increasing electron gain enthalpy)

$L i < N a < K < R b$ (increasing metallic radius)

$A l^{3 +} + < M g^{2 +} < N a^{+} + < F -$ (increasing ionic size)