In which of the following case Kp = Kc ?

Question

In which of the following case Kp = Kc ? (A) N 2+3 H 2 leftharpoons 2 NH 3 (B) PCl 5 leftharpoons PCl 3+ Cl 2 (C) N 2+ O 2 leftharpoons 2 NO (D) 2 SO 2+ O 2 longrightarrow 2 SO 3

Tardigrade Admin · Accepted Answer

Kp=Kc(RT)Δ n, where Δ n = change in gaseous molecules N2+3H2 leftharpoons 2NH3 ; Δ n=-2 ∴ kp< kc N2+O2 leftharpoons 2NO; Δ n=0 ∴ kp=kc 2SO2+O2 leftharpoons 2SO3 ; Δ n=-1 ∴ Kp< Kc

Q. In which of the following case $K_{p} = K_{c}$ ?

$N_{2} + 3 H_{2} ⇌ 2 N H_{3}$

$PC l_{5} ⇌ PC l_{3} + C l_{2}$

$N_{2} + O_{2} ⇌ 2 NO$

$2 S O_{2} + O_{2} ⟶ 2 S O_{3}$

$K_{p} = K_{c} (RT)^{Δ n}$ , where $Δ n$ = change in gaseous molecules
$N_{2} + 3 H_{2} ⇌ 2 N H_{3}; Δ n = - 2$
$∴ k_{p} < k_{c}$
$N_{2} + O_{2} ⇌ 2 NO; Δ n = 0$
$∴ k_{p} = k_{c}$
$2 S O_{2} + O_{2} ⇌ 2 S O_{3}; Δ n = - 1$
$∴ K_{p} < K_{c}$

Q. In which of the following case Kp​=Kc​ ?

N2​+3H2​⇌2NH3​

PCl5​⇌PCl3​+Cl2​

N2​+O2​⇌2NO

2SO2​+O2​⟶2SO3​