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Chemistry
In which of the following case Kp = Kc ?
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Q. In which of the following case $K_p = K_c$ ?
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Equilibrium
A
$N _2+3 H _2 \rightleftharpoons 2 NH _3$
10%
B
$PCl _5 \rightleftharpoons PCl _3+ Cl _2$
12%
C
$N _2+ O _2 \rightleftharpoons 2 NO$
72%
D
$2 SO _2+ O _2 \longrightarrow 2 SO _3$
7%
Solution:
$K_{p}=K_{c}\left(RT\right)^{\Delta n}$, where $\Delta n$ = change in gaseous molecules
$N_{2}+3H_{2} \rightleftharpoons 2NH_{3} ; \Delta n=-2 $
$\therefore k_{p}<\, k_{c}$
$N_{2}+O_{2} \rightleftharpoons 2NO; \Delta n=0$
$\therefore k_{p}=k_{c}$
$2SO_{2}+O_{2} \rightleftharpoons 2SO_{3} ; \Delta n=-1 $
$\therefore K_{p}<\, K_{c}$