In what ratio a 80% (wt./vol.) solution of H2SO4 be mixed to 20% (wt./vol.) of H2SO4 to produce 40% (wt./vol.) H2SO4 solution

Question

In what ratio a 80% (wt./vol.) solution of H2SO4 be mixed to 20% (wt./vol.) of H2SO4 to produce 40% (wt./vol.) H2SO4 solution (A) 2: 1 (B) 1: 2 (C) 1: 3 (D) 3: 1

Tardigrade Admin · Accepted Answer

Let, V1 mL of 80% and V2 mL of 20% are mixed V1× 80+V2× 20=40(.V1+V2.) So 40V1=20V2 So (V1/V2)=(1/2)

Q. In what ratio a 80% (wt./vol.) solution of $H_{2} S O_{4}$ be mixed to 20% (wt./vol.) of $H_{2} S O_{4}$ to produce 40% (wt./vol.) $H_{2} S O_{4}$ solution

2 : 1

1 : 2

1 : 3

3 : 1

Let, $V_{1} m L$ of 80% and $V_{2} m L$ of 20% are mixed

$V_{1} \times 80 + V_{2} \times 20 = 40 (V_{1} + V_{2})$

So $40 V_{1} = 20 V_{2}$

So $\frac{V _{1}}{V _{2}} = \frac{1}{2}$

Q. In what ratio a 80% (wt./vol.) solution of H2​SO4​ be mixed to 20% (wt./vol.) of H2​SO4​ to produce 40% (wt./vol.) H2​SO4​ solution