In van der Waals equation of state of the gas law, the constant b is a measure of

Question

In van der Waals equation of state of the gas law, the constant b is a measure of (A) intermolecular repulsions (B) intermolecular attraction (C) volume occupied by the molecules (D) intermolecular collisions per unit volum

Tardigrade Admin · Accepted Answer

van der Waals equation for one mole of a gas is [ p+(a/V2) ][V-b]=RT where, b is volume correction. It arises due to effective size of molecules.

Q. In van der Waals equation of state of the gas law, the constant b is a measure of

intermolecular repulsions

intermolecular attraction

volume occupied by the molecules

intermolecular collisions per unit volum

van der Waals equation for one mole of a gas is $[p + \frac{a}{V ^{2}}] [V - b] = RT$ where, b is volume correction. It arises due to effective size of molecules.

Q. In van der Waals equation of state of the gas law, the constant b is a measure of

intermolecular repulsions

intermolecular attraction

volume occupied by the molecules

intermolecular collisions per unit volum

van der Waals equation for one mole of a gas is [p+V2a​][V−b]=RT where, b is volume correction. It arises due to effective size of molecules.

van der Waals equation for one mole of a gas is $[p + \frac{a}{V ^{2}}] [V - b] = RT$ where, b is volume correction. It arises due to effective size of molecules.