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Tardigrade
Question
Physics
In U.C.M., when time interval δ tarrow0, the angle between change in velocity (δ v) and linear velocity (v) will be
Q. In
U
.
C
.
M
.
, when time interval
δ
t
→
0
, the angle between change in velocity
(
δ
v
)
and linear velocity
(
v
)
will be
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170
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A
0
∘
B
9
0
∘
C
18
0
∘
D
4
5
∘
Solution:
The direction of change in velocity (
δ
v
) is given by
ϕ
=
2
18
0
∘
−
θ
=
9
0
∘
−
2
θ
...
(
i
)
This can be shown graphically as
For small time interval, i.e.,
δ
t
→
0
, then angle between
v
1
and
v
2
is very small i.e.,
θ
≈
0
∘
. So, from Eq. (i), we get
ϕ
=
9
0
∘