In triangle ABC , AB = AC and equation of AB AC are respectively x +2 y +3=0 and 2 x + y = 2. If the line BC passes through the point (2,3), then the possible equation of BC is(are)

Question

In triangle ABC , AB = AC and equation of AB AC are respectively x +2 y +3=0 and 2 x + y = 2. If the line BC passes through the point (2,3), then the possible equation of BC is(are) (A)  x + y =5 (B) 3 x+y=9 (C) x - y +1=0 (D) x-3 y+7=0

Tardigrade Admin · Accepted Answer

Side BC will be parallel to angle bisector of AB and AC

Q. In $△ A BC, A B = A C$ and equation of $A B & A C$ are respectively $x + 2 y + 3 = 0$ and $2 x + y =$ 2. If the line $BC$ passes through the point $(2, 3)$ , then the possible equation of $BC$ is(are)

$x + y = 5$

$3 x + y = 9$

$x - y + 1 = 0$

$x - 3 y + 7 = 0$

Side BC will be parallel to angle bisector of AB and AC

Q. In △ABC,AB=AC and equation of AB&AC are respectively x+2y+3=0 and 2x+y= 2. If the line BC passes through the point (2,3), then the possible equation of BC is(are)

x+y=5

3x+y=9

x−y+1=0

x−3y+7=0

Side BC will be parallel to angle bisector of AB and AC

Q. In $△ A BC, A B = A C$ and equation of $A B & A C$ are respectively $x + 2 y + 3 = 0$ and $2 x + y =$ 2. If the line $BC$ passes through the point $(2, 3)$ , then the possible equation of $BC$ is(are)

$x + y = 5$

$3 x + y = 9$

$x - y + 1 = 0$

$x - 3 y + 7 = 0$