Question

In triangle $ABC$, $a=2$, $b=3$ and sin $A=\frac{2}{3}$, then $B$ is equal to

• A. $30^{\circ }$
• B. $60^{\circ }$
• C. $90^{\circ }$
• D. $120^{\circ }$

Answer 1

Answer: (C)

Using sine rules

$\frac{sinA}{a}=\frac{sinB}{b}$

$\Rightarrow \frac{2/3}{2}=\frac{sinB}{3}$

$\Rightarrow sinB=1$

$\Rightarrow B=90^{\circ }$