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Q. In triangle $ABC$, $a=2$, $b=3$ and sin $A=\frac{2}{3}$, then $B$ is equal to

WBJEEWBJEE 2009Trigonometric Functions

Solution:

Using sine rules

$\frac{sin\,A}{a}=\frac{sin\,B}{b}$

$\Rightarrow \frac{2/ 3}{2}=\frac{sin\,B}{3}$

$\Rightarrow sin\,B=1$

$\Rightarrow B=90^{\circ} $