In this reaction CH3CHO +HCN - CH3CH(OH)CN -[ textH ⋅ OH] CH3CH(OH)COOH an asymmetric centre is generated. The acid obtained would be

Question

In this reaction CH3CHO +HCN -> CH3CH(OH)CN ->[ textH ⋅ OH] CH3CH(OH)COOH an asymmetric centre is generated. The acid obtained would be (A)  50 % D+50 % L -isomer (B)  20 % D+80 % L -isomer (C)  D -isomer (D)  L -isomer

Tardigrade Admin · Accepted Answer

Lactic acid obtained in the given reaction is an optically active compound due to the presence of chiral C-atom. It exits as d and l forms whose ratio is 1 :1.

Q. In this reaction
$CH X_{3} CHO + HCN CH X_{3} CH (OH) CN$
$H \cdot OH CH X_{3} CH (OH) COOH$
an asymmetric centre is generated. The acid obtained would be

$50% D + 50% L$ -isomer

$20% D + 80% L$ -isomer

$D$ -isomer

$L$ -isomer

Lactic acid obtained in the given reaction is an optically active compound due to the presence of chiral $C$ -atom. It exits as $d$ and $l$ forms whose ratio is $1 : 1$ .

Q. In this reaction CHX3​CHO+HCN​CHX3​CH(OH)CN H ⋅ OH​CHX3​CH(OH)COOH an asymmetric centre is generated. The acid obtained would be

50%D+50%L -isomer

20%D+80%L -isomer

D -isomer

L -isomer