In the Young's double slit experiment, the interference pattern is found to have an intensity ratio between bright and dark fringes as 9 . This implies that

Question

In the Young's double slit experiment, the interference pattern is found to have an intensity ratio between bright and dark fringes as 9 . This implies that (A) the intensities at the screen due to two slits are 5 units and 4 units respectively (B) the intensities at the screen due to two slits are 4 units and 1 unit respectively (C) the amplitude ratio is 3 (D) the amplitude ratio is 2

Tardigrade Admin · Accepted Answer

As, (I max /I min )=((a+b)2/(a-b)2)=9 or (a +b/a-b)=3 or 3 a-3 b=a +b or 2 a=4 b ∴ (I1/I2)=(a2/b2)=(4 b2/b2)=4: 1

Q. In the Young's double slit experiment, the interference pattern is found to have an intensity ratio between bright and dark fringes as $9.$ This implies that

the intensities at the screen due to two slits are 5 units and 4 units respectively

the intensities at the screen due to two slits are 4 units and 1 unit respectively

the amplitude ratio is 3

the amplitude ratio is 2

As, $\frac{I _{m a x}}{I _{m i n}} = \frac{( a + b ) ^{2}}{( a - b ) ^{2}} = 9$
or $\frac{a + b}{a - b} = 3$
or $3 a - 3 b = a + b$
or $2 a = 4 b$
$∴ \frac{I _{1}}{I _{2}} = \frac{a ^{2}}{b ^{2}} = \frac{4 b ^{2}}{b ^{2}} = 4 : 1$

Q. In the Young's double slit experiment, the interference pattern is found to have an intensity ratio between bright and dark fringes as 9. This implies that