Question

In the unbalanced chemical equation below $x,y$ and $z$ are coefficient to be determined.
$F{e}^{2+}+xB{r}_2\to yF{e}^{3+}+zB{r}^{-}$
When the equation is properly balanced what is value of $z$ ?

• A. $1$
• B. $2$
• C. $4$
• D. $3$

Answer 1

Answer: (A)

$F{e}^{2+}+\frac{1}{2}B{r}_2\to F{e}^{3+}+B{r}^{-}$