In the system shown in the adjoining figure, the acceleration of 1 kg mass is

Question

In the system shown in the adjoining figure, the acceleration of 1 kg mass is (A) (g/4) downwards (B) (g/2) downwards (C) (g/2) upwards (D) (g/4) upwards

Tardigrade Admin · Accepted Answer

If a is downward acceleration of 4 kg block, the upward acceleration of 1 kg block must be 2a.

If T is tension in each part of string, then equations of motion of the two blocks are

4 a = 4 g - 2 T ... (i)

1 \times 2 a = T - 1 g ... (ii)

or

4 a = 2 T - 2 g ... (iii)

Adding (i) and (iii), we get

8 a = 2 g, a = \frac{g}{4}

∴

Acceleration of 1 kg block

= 2 a = \frac{g}{2}

upwards.

Q. In the system shown in the adjoining figure, the acceleration of 1 kg mass is

$\frac{g}{4}$ downwards

$\frac{g}{2}$ downwards

$\frac{g}{2}$ upwards

$\frac{g}{4}$ upwards

Q. In the system shown in the adjoining figure, the acceleration of 1 kg mass is

4g​ downwards

2g​ downwards

2g​ upwards

4g​ upwards

$\frac{g}{4}$ downwards

$\frac{g}{2}$ downwards

$\frac{g}{2}$ upwards

$\frac{g}{4}$ upwards