In the Solvay process for producing sodium carbonate ( Na 2 CO 3), the following reactions occur in sequence NH 3+ CO 2+ H 2 O longrightarrow NH 4 HCO 3 NH 4 HCO 3+ NaCl longrightarrow NH 4 Cl + NaHCO 3 2 NaHCO 3 stackrelΔ longrightarrow Na 2 CO 3+ H 2 O + CO 2 How much of Na 2 CO 3 would be produced per kg of NH 3 used if the process were 100 % efficient?

Question

In the Solvay process for producing sodium carbonate ( Na 2 CO 3), the following reactions occur in sequence NH 3+ CO 2+ H 2 O longrightarrow NH 4 HCO 3 NH 4 HCO 3+ NaCl longrightarrow NH 4 Cl + NaHCO 3 2 NaHCO 3 stackrelΔ longrightarrow Na 2 CO 3+ H 2 O + CO 2 How much of Na 2 CO 3 would be produced per kg of NH 3 used if the process were 100 % efficient? (A) 3.12 kg (B) 1.00 kg (C) 2.00 kg (D) 0.56 kg

Tardigrade Admin · Accepted Answer

Given reaction is not balanced

Based on stoichiometry

1 m o l N a_{2} C O_{3}

is from

2 m o l N a H C O_{3}

2 m o l N a H C O_{3}

is from

2 m o l N H_{4} H C O_{3}

2 m o l N H_{4} H C O_{3}

is from

2 m o l N H_{3}

Thus,

1 m o l N a_{2} C O_{3}

is from

= 2 m o l N H_{3}

106 g N a_{2} C O_{3}

is from

= 2 \times 17 g N H_{3}

34 g N H_{3}

gives

= 106 g N a_{2} C O_{3}

Thus,

1000 g N H_{3}

gives

= \frac{106 \times 1000}{34} g N a_{2} C O_{3}

= 3118 g N a_{2} C O_{3}

= 3.118 k g N a_{2} C O_{3}