In the shown figure, the charge appearing on the conducting shell (grounded) of Radius R , when a point charge q is kept at a distance of d from the centre of the sphere is:

Question

In the shown figure, the charge appearing on the conducting shell (grounded) of Radius R , when a point charge q is kept at a distance of d from the centre of the sphere is: <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-kdrp56c4kkkp.png" /> (A) q (B) (qd/r) (C) - (qr/d) (D) 0

Tardigrade Admin · Accepted Answer

The net potential on the surface of earthed conductor is zero. <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-kdrp56c4r3a9.png" /> ∴ V =( q 0/4 π ε0 r )+( q /4 π ε0 d )=0 ∴ q 0=-( qr / d )

Q. In the shown figure, the charge appearing on the conducting shell (grounded) of Radius $R$ , when a point charge $q$ is kept at a distance of $d$ from the centre of the sphere is:

$q$

$\frac{q d}{r}$

$- \frac{q r}{d}$

0

The net potential on the surface of earthed conductor is zero.

$∴ V = \frac{q _{0}}{4 π ε _{0} r} + \frac{q}{4 π ε _{0} d} = 0$
$∴ q_{0} = - \frac{q r}{d}$

Q. In the shown figure, the charge appearing on the conducting shell (grounded) of Radius R , when a point charge q is kept at a distance of d from the centre of the sphere is:

q

rqd​

−dqr​

0

The net potential on the surface of earthed conductor is zero. ∴V=4πε0​rq0​​+4πε0​dq​=0 ∴q0​=−dqr​

Q. In the shown figure, the charge appearing on the conducting shell (grounded) of Radius $R$ , when a point charge $q$ is kept at a distance of $d$ from the centre of the sphere is:

$q$

$\frac{q d}{r}$

$- \frac{q r}{d}$

The net potential on the surface of earthed conductor is zero.

$∴ V = \frac{q _{0}}{4 π ε _{0} r} + \frac{q}{4 π ε _{0} d} = 0$
$∴ q_{0} = - \frac{q r}{d}$