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Tardigrade
Question
Physics
In the series L-C-R circuit shown, the impedance is
Q. In the series
L
−
C
−
R
circuit shown, the impedance is
3863
202
KCET
KCET 2011
Electromagnetic Induction
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A
200
Ω
15%
B
100
Ω
24%
C
300
Ω
32%
D
500
Ω
28%
Solution:
X
L
=
2
π
f
L
=
2
π
(
π
50
)
×
1
=
100
Ω
X
C
=
2
π
f
C
1
=
2
π
(
π
50
)
20
×
1
0
−
6
1
=
500
Ω
Impedance,
Z
=
R
2
+
(
X
C
−
X
L
)
2
Z
=
(
300
)
2
−
(
400
)
2
=
500
Ω