In the sequence of following nuclear reactions, 92X238 xrightarrow-α Y xrightarrow-β Z xrightarrow-β L xrightarrow-nα 84M 218 The value of n will be

Question

In the sequence of following nuclear reactions, 92X238 xrightarrow-α Y xrightarrow-β Z xrightarrow-β L xrightarrow-nα 84M 218 The value of n will be (A) 3 (B) 4 (C) 5 (D) 6

Tardigrade Admin · Accepted Answer

92X238 xrightarrow-α 90Y234 xrightarrow-β 91Z234 xrightarrow-β 92L234 xrightarrow-4α 84M218 The value of. n is 4.

Q. In the sequence of following nuclear reactions, $_{92} X^{238} - α Y - β Z - β L - n α_{84} M^{218}$ The value of n will be

3

4

5

6

$_{92} X^{238} - α_{90} Y^{234} - β_{91} Z^{234} - β_{92} L^{234}$ $- 4 α_{84} M^{218}$ The value of. $n$ is 4.

Q. In the sequence of following nuclear reactions, 92​X238−α​Y−β​Z−β​L−nα​84​M218 The value of n will be

3

4

5

6

92​X238−α​90​Y234−β​91​Z234−β​92​L234 −4α​84​M218 The value of. n is 4.

Q. In the sequence of following nuclear reactions, $_{92} X^{238} - α Y - β Z - β L - n α_{84} M^{218}$ The value of n will be

$_{92} X^{238} - α_{90} Y^{234} - β_{91} Z^{234} - β_{92} L^{234}$ $- 4 α_{84} M^{218}$ The value of. $n$ is 4.