1. Tardigrade
  2. Question
  3. Chemistry
  4. In the sequence of following nuclear reactions, 92X238 xrightarrow-α Y xrightarrow-β Z xrightarrow-β L xrightarrow-nα 84M 218 The value of n will be

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Q. In the sequence of following nuclear reactions, $ _{92}{{X}^{238}}\xrightarrow{-\alpha }Y\xrightarrow{-\beta }Z\xrightarrow{-\beta }L\xrightarrow{-n\alpha }{{\,}_{84}}M{{\,}^{218}} $ The value of n will be

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Solution:

$ {{\,}_{92}}{{X}^{238}}\xrightarrow{-\alpha }{{\,}_{90}}{{Y}^{234}}\xrightarrow{-\beta }{{\,}_{91}}{{Z}^{234}}\xrightarrow{-\beta }{{\,}_{92}}{{L}^{234}} $ $ \xrightarrow{-4\alpha }{{\,}_{84}}{{M}^{218}} $ The value of. $ n $ is 4.