In the reaction xHI + yHNO3 → NO + I2 + H2O

Question

In the reaction xHI + yHNO3 → NO + I2 + H2O (A) x = 3,y = 2 (B) x = 2,y = 3 (C) x = 6 , y = 2 (D) x = 6 , y = 1

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/22ea6c60230823cea78c7c4ddb86fb42-.jpeg" /> Adding (1) and (2) ⇒ 6I- + 2NO-3 → 2NO + 3I2, 6HI + 2HNO3 → 2NO + 3I2 + 4H20 ⇒ x = 6, y = 2

Q. In the reaction
$x H I + yH N O_{3} \to NO + I_{2} + H_{2} O$

$x = 3, y = 2$

$x = 2, y = 3$

$x = 6, y = 2$

$x = 6, y = 1$

Adding (1) and (2)
$\Rightarrow 6 I^{-} + 2 N O_{3}^{-} \to 2 NO + 3 I_{2}$ ,
$6 H I + 2 H N O_{3} \to 2 NO + 3 I_{2} + 4 H_{2} 0$
$\Rightarrow x = 6, y = 2$

Q. In the reaction xHI+yHNO3​→NO+I2​+H2​O

x=3,y=2

x=2,y=3

x=6,y=2

x=6,y=1