In the reaction S8 + 12 OH- arrow 4 S2- + 2 S2O2-3 + 6 H2O S has undergone oxidation and reduction. Which of the following statement is true ?

Question

In the reaction S8 + 12 OH- arrow 4 S2- + 2 S2O2-3 + 6 H2O S has undergone oxidation and reduction. Which of the following statement is true ? (A) In S2-, sulphur has been oxidised and in S2O2-, sulphur has been reduced. (B) In S2- , sulphur has been reduced and in S2O2-3 sulphur has been oxidised as well as reduced. (C) In both S2- and S2O2-3, sulphur has been oxidised. (D) In both S2- and S2O2-3 ions, sulphur has been reduced.

Tardigrade Admin · Accepted Answer

Correct answer is (b) In S2- , sulphur has been reduced and in S2O2-3 sulphur has been oxidised as well as reduced.

Q. In the reaction $S_{8} + 12 O H^{-} \to 4 S^{2 -} + 2 S_{2} O_{3}^{2 -} + 6 H_{2} O$ $S$ has undergone oxidation and reduction. Which of the following statement is true ?

In $S^{2 -}$ , sulphur has been oxidised and in $S_{2} O^{2 -}$ , sulphur has been reduced.

In $S^{2 -}$ , sulphur has been reduced and in $S_{2} O_{3}^{2 -}$ sulphur has been oxidised as well as reduced.

In both $S^{2 -}$ and $S_{2} O_{3}^{2 -}$ , sulphur has been oxidised.

In both $S^{2 -}$ and $S_{2} O_{3}^{2 -}$ ions, sulphur has been reduced.

Correct answer is (b) In $S^{2 -}$ , sulphur has been reduced and in $S_{2} O_{3}^{2 -}$ sulphur has been oxidised as well as reduced.

Q. In the reaction S8​+12OH−→4S2−+2S2​O32−​+6H2​O S has undergone oxidation and reduction. Which of the following statement is true ?

In S2−, sulphur has been oxidised and in S2​O2−, sulphur has been reduced.

In S2− , sulphur has been reduced and in S2​O32−​ sulphur has been oxidised as well as reduced.

In both S2− and S2​O32−​, sulphur has been oxidised.

In both S2− and S2​O32−​ ions, sulphur has been reduced.