In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO 2 is

Question

In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO 2 is (A) 2 (B) 5 (C) 1 (D) 10

Tardigrade Admin · Accepted Answer

Reaction of oxalate with permanganate in acidic medium.

5 C_{2} O_{4}^{2 -}

ions transfer

10 e^{-}

to produce

10

molecules of

C O_{2}

.
So, number of electrons involved in producing

10

molecules of

C O_{2}

is

10

.
Thus, number of electrons involved in producing

1

molecule of

C O_{2}

is

1

.

Q. In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of $C O_{2}$ is

$2$

$5$

$1$

$10$

Q. In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO2​ is

2

5

1

10

Reaction of oxalate with permanganate in acidic medium. 5C2​O42−​ ions transfer 10e−to produce 10 molecules of CO2​. So, number of electrons involved in producing 10 molecules of CO2​ is 10. Thus, number of electrons involved in producing 1 molecule of CO2​ is 1.

Q. In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of $C O_{2}$ is

$2$

$5$

$1$

$10$