In the reaction of KMnO4 with an oxalate in acidic medium, - MnO-4 is reduced to Mn2+ and C2O2-4 is oxidised to CO2. Hence, 50 mL of 0.02 M KMnO4 is equivalent to

Question

In the reaction of KMnO4 with an oxalate in acidic medium, - MnO-4 is reduced to Mn2+ and C2O2-4 is oxidised to CO2. Hence, 50 mL of 0.02 M KMnO4 is equivalent to (A) 100 mL of 0.05 M H2C2O4 (B) 50 mL of 0.05 M H2C2O4 (C) 25 mL of 0.02 M H2C2O4 (D) 50 mL of 0.10 M H2C2O4

Tardigrade Admin · Accepted Answer

Correct answer is (b) 50 mL of 0.05 M H2C2O4

Q. In the reaction of $K M n O_{4}$ with an oxalate in acidic medium, - $M n O_{4}^{-}$ is reduced to $M n^{2 +}$ and $C_{2} O_{4}^{2 -}$ is oxidised to $C O_{2}$ . Hence, $50 m L$ of $0.02 M K M n O_{4}$ is equivalent to

100 mL of 0.05 M $H_{2} C_{2} O_{4}$

50 mL of 0.05 M $H_{2} C_{2} O_{4}$

25 mL of 0.02 M $H_{2} C_{2} O_{4}$

50 mL of 0.10 M $H_{2} C_{2} O_{4}$

Correct answer is (b) 50 mL of 0.05 M $H_{2} C_{2} O_{4}$

Q. In the reaction of KMnO4​ with an oxalate in acidic medium, - MnO4−​ is reduced to Mn2+ and C2​O42−​ is oxidised to CO2​. Hence, 50mL of 0.02MKMnO4​ is equivalent to

100 mL of 0.05 M H2​C2​O4​

50 mL of 0.05 M H2​C2​O4​

25 mL of 0.02 M H2​C2​O4​

50 mL of 0.10 M H2​C2​O4​