Question

In the reaction : $I_2+2S_2{O}_3^{2-}\to 2I^{-}+S_4{O}_6^{2-}$

• A. $I_2$ is reducing agent.
• B. $I_2$ is oxidising agent and $S_2{O}_3^{2-}$ is reducing agent.
• C. $S_2{O}_3^{2-}$ is oxidising agent.
• D. $I_2$ is reducing agent and $S_2{O}_3^{2-}$ is oxidising agent.

Answer 1

Answer: (B)

$I_2$ undergoes reduction hence acts as oxidising agent.
$S_2^{+2}{O}_3^{2-}\to S_4^{+2.5}{O}_6^{2-}$
It undergoes oxidation hence acts as a reducing agent.