Question

In the reaction : $I_{2} + 2S_{2}O^{2-}_{3} \to 2I^{-} + S_{4}O^{2-}_{6}$

• A. $I_2$ is reducing agent.
• B. $I_2$ is oxidising agent and $S_{2}O^{2-}_{3}$ is reducing agent.
• C. $S_{2}O^{2-}_{3}$ is oxidising agent.
• D. $I_2$ is reducing agent and $S_{2}O^{2-}_{3}$ is oxidising agent.

Answer 1

Answer: (B)

$I_2$ undergoes reduction hence acts as oxidising agent.
$S_{2}^{+2}O^{2-}_{3} \to S_{4}^{+2.5}O^{2-}_{6}$
It undergoes oxidation hence acts as a reducing agent.