Tardigrade
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Tardigrade
Question
Chemistry
In the reaction. CH 3 COOH xrightarrow LiAlH 4 A xrightarrow PCl 5 B xrightarrow text Alc.KOH C, the product C is
Q. In the reaction.
C
H
3
COO
H
L
i
A
l
H
4
A
PC
l
5
B
Alc.KOH
C
, the product
C
is
3592
250
JEE Main
JEE Main 2014
Aldehydes Ketones and Carboxylic Acids
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A
Acetaldehyde
24%
B
Acetylene
14%
C
Ethylene
55%
D
Acetyl chloride
7%
Solution:
C
H
3
COO
H
L
i
A
l
H
4
C
H
3
C
H
2
O
H
PC
l
5
C
H
3
C
H
2
Cl
alc
K
O
H
C
H
2
=
C
H
2