1. Tardigrade
  2. Question
  3. Chemistry
  4. In the reaction. CH 3 COOH xrightarrow LiAlH 4 A xrightarrow PCl 5 B xrightarrow text Alc.KOH C, the product C is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In the reaction.
$CH _{3} COOH \xrightarrow{ LiAlH _{4}} A \xrightarrow{ PCl _{5}} B \xrightarrow{\text { Alc.KOH }}C$, the product $C$ is

JEE MainJEE Main 2014Aldehydes Ketones and Carboxylic Acids

Solution:

$CH_3COOH \xrightarrow{LiAlH_4}CH_3CH_2OH \xrightarrow {PCl_5}CH_3CH_2Cl \xrightarrow{\text{alc}KOH} CH_2=CH_2$