In the reaction, C6H5OH-[NaOH](A)-[CO2][140°C,(4-7)atm](B)-[HCl](C), the compound (C) is

Question

In the reaction, C6H5OH->[NaOH](A)->[CO2][140°C,(4-7)atm](B)->[HCl](C), the compound (C) is (A) Benzoic acid (B) Salicylaldehyde (C) Chlorobenzene (D) Salicylic acid

Tardigrade Admin · Accepted Answer

Treatment of sodium salt of phenol with CO2 under pressure brings about substitution of the -COOH group for the hydrogen of the ring. This is called as Kolbe's reaction

Q. In the reaction, $C X_{6} H X_{5} OH NaOH (A) CO X_{2} 140 X^{°} C, (4 - 7) atm (B) HCl (C)$ , the compound $(C)$ is

Benzoic acid

Salicylaldehyde

Chlorobenzene

Salicylic acid

Treatment of sodium salt of phenol with $C O_{2}$ under pressure brings about substitution of the $- COO H$ group for the hydrogen of the ring. This is called as Kolbe's reaction

Q. In the reaction, CX6​HX5​OHNaOH​(A)COX2​140X°C,(4−7)atm​(B)HCl​(C), the compound (C) is