Tardigrade
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Tardigrade
Question
Chemistry
In the reaction BrCH2-CH2Br + Zn → Y + ZnBr2, Y is
Q. In the reaction
B
r
C
H
2
−
C
H
2
B
r
+
Z
n
→
Y
+
Z
n
B
r
2
,
Y is
6492
211
Hydrocarbons
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A
Ethyne
33%
B
Ethene
52%
C
Ethane
10%
D
None
5%
Solution:
B
r
−
C
H
2
−
C
H
2
−
B
r
+
Z
n
→
H
2
C
=
(
Y
)
C
H
2
+
Z
n
B
r
2