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  4. In the reaction BrCH2-CH2Br + Zn → Y + ZnBr2, Y is

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Q. In the reaction $BrCH_2-CH_2Br + Zn \to Y + ZnBr_2, $Y is

Hydrocarbons

Solution:

$Br - CH_2- CH_2-Br + Zn \rightarrow H_2C= \underset{(Y)}{CH_2} + ZnBr_2$