In the reaction 4A+2B+3C arrow A4 B2 C3, what will be the number moles of product formed, starting from one mole of A,0.6 moles of B and 0.72 moles of C?

Question

In the reaction 4A+2B+3C arrow A4 B2 C3, what will be the number moles of product formed, starting from one mole of A,0.6 moles of B and 0.72 moles of C? (A) 0.25 (B) 0.3 (C) 0.24 (D) 2.32

Tardigrade Admin · Accepted Answer

Stoichiometric mole ratio textA textB textC =(1/4) , (0.6/2) , (0.72/3) = 0.25, 0.30,0.24 C is limiting Reagent So, according to Stoichiometry of reaction 3 mol C gives = 1 mol A4B2C3 . &there4; 0.72 mol of C gives= (1/3) × 0.72 = 0.24

Q. In the reaction $4 A + 2 B + 3 C \to A_{4} B_{2} C_{3},$ what will be the number moles of product formed, starting from one mole of $A, 0.6$ moles of $B$ and $0.72$ moles of $C ?$

$0.25$

$0.3$

$0.24$

$2.32$

Stoichiometric mole ratio $A B C = \frac{1}{4}, \frac{0.6}{2}, \frac{0.72}{3} = 0.25, 0.30, 0.24$
$C$ is limiting Reagent
So, according to Stoichiometry of reaction
$3$ mol $C$ gives = $1$ mol $A_{4} B_{2} C_{3}$ .
∴ $0.72$ mol of $C$ gives= $\frac{1}{3} \times 0.72 = 0.24$

Q. In the reaction 4A+2B+3C→A4​B2​C3​, what will be the number moles of product formed, starting from one mole of A,0.6 moles of B and 0.72 moles of C?

0.25

0.3

0.24

2.32