In the reaction, 2X + B2H6 longrightarrow [BH2(X)2] [BH4] the amine(s) X is/are

Question

In the reaction, 2X + B2H6 longrightarrow [BH2(X)2] [BH4] the amine(s) X is/are (A) NH3 (B) CH3NH2 (C) (CH3)2NH (D) (CH3)3N

Tardigrade Admin · Accepted Answer

Diborane (B2H6) undergoes unsymmetric cleavage with NH3, primary and secondary amine while tertiary amine brings about symmetrical cleavage of B2H6 as :

Q. In the reaction,
$2 X + B_{2} H_{6} ⟶ [B H_{2} (X)_{2}] [B H_{4}]$
the amine(s) $X$ is/are

$N H_{3}$

$C H_{3} N H_{2}$

$(C H_{3})_{2} N H$

$(C H_{3})_{3} N$

Diborane $(B_{2} H_{6})$ undergoes unsymmetric cleavage with $N H_{3}$ , primary and secondary amine while tertiary amine brings about symmetrical cleavage of $B_{2} H_{6}$ as :

Q. In the reaction, 2X+B2​H6​⟶[BH2​(X)2​][BH4​] the amine(s) X is/are

NH3​

CH3​NH2​

(CH3​)2​NH

(CH3​)3​N