In the reaction 2Na2S2O3 + I2 → Na2S4O6 + 2NaI, the equivalent weight of Na2S2O3(mol. wt. = M) is equal to

Question

In the reaction 2Na2S2O3 + I2 → Na2S4O6 + 2NaI, the equivalent weight of Na2S2O3(mol. wt. = M) is equal to (A) M (B) M / 2 (C) M / 3 (D) M / 4

Tardigrade Admin · Accepted Answer

Na2+2SO3 +I2 → Na2+2.5S4O6+NaI n = 2 × 0.5 = 1 E=(M/n-factor)=(M/1)=M

Q. In the reaction $2 N a_{2} S_{2} O_{3} + I_{2} \to N a_{2} S_{4} O_{6} + 2 N a I$ , the equivalent weight of $N a_{2} S_{2} O_{3}$ (mol. wt. = $M$ ) is equal to