Q.
In the reaction 2N2O5→4NO2+O2 the rate is expressed as
(i)dtd[N2O5]k1[N2O5]
(ii)dtd[NO2]=k2[N2O5]0
(iii)dtd[O2]=k3[N2O5]
Relation between k1k2 and 3 is
Rate =21dtd[N2O5]=41dtd[NO2]=dtd[O2]
Rate =21k1[N2O2]=41k2[N2O5]=41[N2O5]=K3[N2O5]
On dividing all the terms by [N2O5] and multiplying by 4 we get, 2k1=k2=4k3