Question

In the reaction
$2CuS{O}_4+4KI\to 2C{u}_2{I}_2+I_2+2K_{2}S{O}_4$ the equivalent weight of $CuS{O}_4$ will be:

• A. $79.75$
• B. $159.5$
• C. $329$
• D. None of these

Answer 1

Answer: (B)

$2CuS{O}_4+4KI\to C{u}_2{I}_2+I_2+2K_{2}S{O}_4$
$C{u}^{2+}+1e^{-}\to C{u}^{+}$
$E_{cu}=?V.F.=1$
$E_{CuS{O}_4}=\frac{159.5}{1}=159.5$