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Q. In the reaction
$2CuSO_4 + 4KI \to 2Cu_2I_2 + I_2 + 2K_2SO_4$ the equivalent weight of $CuSO_4$ will be:

Some Basic Concepts of Chemistry

Solution:

$2CuSO_{4}+4KI\to Cu_{2}I_{2}+I_{2}+2K_{2}SO_{4}$
$Cu^{2+}+1e^{-}\to Cu^{+}$
$E_{cu}=? \,\,\,\,\, V.F.=1$
$E_{CuSO_4}=\frac{159.5}{1}=159.5$