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Tardigrade
Question
Chemistry
In the reaction 2 K 3[ Fe ( CN )6]+2 KOH + H 2 O 2 arrow 2 K 4[ Fe ( CN )6]+2 H 2 O + O 2, H 2 O 2 acts as
Q. In the reaction
2
K
3
[
F
e
(
CN
)
6
]
+
2
K
O
H
+
H
2
O
2
→
2
K
4
[
F
e
(
CN
)
6
]
+
2
H
2
O
+
O
2
,
H
2
O
2
acts as
1729
228
Hydrogen
Report Error
A
Reducing agent
B
Oxidising agent
C
Knocking agent
D
Bleaching agent
Solution:
H
2
O
2
reduces potassium ferricyanide to potassium ferrocyanide
2
K
3
[
F
e
(
CN
)
6
]
+
2
K
O
H
+
H
2
O
2
→
2
K
4
[
F
e
(
CN
)
6
]
+
2
H
2
O
+
O
2