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Q. In the reaction
$2 K _{3}\left[ Fe ( CN )_{6}\right]+2 KOH + H _{2} O _{2} \rightarrow 2 K _{4}\left[ Fe ( CN )_{6}\right]+2 H _{2} O + O _{2}, H _{2} O _{2}$ acts as

Hydrogen

Solution:

$H _{2} O _{2}$ reduces potassium ferricyanide to potassium ferrocyanide
$2 K _{3}\left[ Fe ( CN )_{6}\right]+2 KOH + H _{2} O _{2} \rightarrow 2 K _{4}\left[ Fe ( CN )_{6}\right]+2 H _{2} O + O _{2}$