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Electrostatic Potential and Capacitance
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Solution:
Charge on each capacitor, C1,C2,C3 is same =q Let charge on C4 be q' ∴C1q+C2q+C3q=600
or q[C11+C21+C31]=600
or Csq=600 ∴q=600Cs=600×320μC 4000×10−6C=4×10−3C
Also C4q′=600
or q′=C4×600μC =200×600μC =12×10−3C