The point from where a ball is projected is taken as the origin of the coordinate axes. The x and y components of its displacement are given by x = 6t and y = 7t - 5t2 .what is the angle of projection?

Question

The point from where a ball is projected is taken as the origin of the coordinate axes. The x and y components of its displacement are given by x = 6t and y = 7t - 5t2 .what is the angle of projection? (A) tan-1 ((1/4)) (B) tan-1 ((4/3)) (C) tan-1 ((1/8)) (D) tan-1 ((1/6))

Tardigrade Admin · Accepted Answer

tan θ=(vy/vx)=(8/6) =(4/3) or θ=tan-1 (4/3)

Q. The point from where a ball is projected is taken as the origin of the coordinate axes. The x and y components of its displacement are given by $x = 6 t$ and $y = 7 t - 5 t^{2}$ .what is the angle of projection?

$t a n^{- 1} (\frac{1}{4})$

$t a n^{- 1} (\frac{4}{3})$

$t a n^{- 1} (\frac{1}{8})$

$t a n^{- 1} (\frac{1}{6})$

tan $θ = \frac{v _{y}}{v _{x}} = \frac{8}{6} = \frac{4}{3}$ or $θ = t a n^{- 1} \frac{4}{3}$

Q. The point from where a ball is projected is taken as the origin of the coordinate axes. The x and y components of its displacement are given by x=6t and y=7t−5t2 .what is the angle of projection?

tan−1(41​)

tan−1(34​)

tan−1(81​)

tan−1(61​)