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Tardigrade
Question
Chemistry
In the oxidation of C 6 H 5- CH 2 arrow CH 3 by KMnO 4 the product formed is
Q. In the oxidation of
C
6
H
5
−
C
H
2
→
C
H
3
by
K
M
n
O
4
the product formed is
124
162
Manipal
Manipal 2019
Report Error
A
C
6
H
5
−
C
H
2
−
C
H
O
B
C
6
H
5
−
C
H
2
−
COO
H
C
C
6
H
6
−
COO
H
D
C
6
H
5
−
C
H
2
−
O
H
Solution:
Correct answer is (c)
C
6
H
6
−
COO
H