In the organic compound CH 2= CH - CH 2- CH 2- C ≡ CH, the pair of hybridised orbitals involved in the formation C 2- C 3 bond is

Question

In the organic compound CH 2= CH - CH 2- CH 2- C ≡ CH, the pair of hybridised orbitals involved in the formation C 2- C 3 bond is (A) s p-s p2 (B) s p-s p3 (C) s p2-s p3 (D) s p3-s p3

Tardigrade Admin · Accepted Answer

The carbon atom in the given compound may be numbered as: H2 overset1C = overset2CH- overset3CH2- overset4CH2 - overset5C ≡ overset6CH Thus, C2 - C3 are bonded by sp2 - sp3 hybrid orbitals.

Q. In the organic compound
$C H_{2} = C H - C H_{2} - C H_{2} - C \equiv C H$ , the pair of hybridised orbitals involved in the formation $C_{2} - C_{3}$ bond is

$s p - s p^{2}$

$s p - s p^{3}$

$s p^{2} - s p^{3}$

$s p^{3} - s p^{3}$

The carbon atom in the given compound may be numbered as:
$H_{2} C 1 = C 2 H - C 3 H_{2} - C 4 H_{2} - C 5 \equiv C 6 H$

Thus, $C_{2} - C_{3}$ are bonded by $s p^{2} - s p^{3}$ hybrid orbitals.

Q. In the organic compound CH2​=CH−CH2​−CH2​−C≡CH, the pair of hybridised orbitals involved in the formation C2​−C3​ bond is

sp−sp2

sp−sp3

sp2−sp3

sp3−sp3